Optimal. Leaf size=287 \[ -\frac{\sqrt{c-i d} (i A+B-i C) \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{f \sqrt{a-i b}}-\frac{\sqrt{c+i d} (B-i (A-C)) \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{f \sqrt{a+i b}}+\frac{(-a C d+2 b B d+b c C) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b \tan (e+f x)}}{\sqrt{b} \sqrt{c+d \tan (e+f x)}}\right )}{b^{3/2} \sqrt{d} f}+\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f} \]
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Rubi [A] time = 2.63334, antiderivative size = 287, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 8, integrand size = 49, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.163, Rules used = {3647, 3655, 6725, 63, 217, 206, 93, 208} \[ -\frac{\sqrt{c-i d} (i A+B-i C) \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{f \sqrt{a-i b}}-\frac{\sqrt{c+i d} (B-i (A-C)) \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{f \sqrt{a+i b}}+\frac{(-a C d+2 b B d+b c C) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b \tan (e+f x)}}{\sqrt{b} \sqrt{c+d \tan (e+f x)}}\right )}{b^{3/2} \sqrt{d} f}+\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f} \]
Antiderivative was successfully verified.
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Rule 3647
Rule 3655
Rule 6725
Rule 63
Rule 217
Rule 206
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{\sqrt{c+d \tan (e+f x)} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right )}{\sqrt{a+b \tan (e+f x)}} \, dx &=\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f}+\frac{\int \frac{\frac{1}{2} (2 A b c-C (b c+a d))+b (B c+(A-C) d) \tan (e+f x)+\frac{1}{2} (b c C+2 b B d-a C d) \tan ^2(e+f x)}{\sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}} \, dx}{b}\\ &=\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f}+\frac{\operatorname{Subst}\left (\int \frac{\frac{1}{2} (2 A b c-C (b c+a d))+b (B c+(A-C) d) x+\frac{1}{2} (b c C+2 b B d-a C d) x^2}{\sqrt{a+b x} \sqrt{c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{b f}\\ &=\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f}+\frac{\operatorname{Subst}\left (\int \left (\frac{b c C+2 b B d-a C d}{2 \sqrt{a+b x} \sqrt{c+d x}}+\frac{b (A c-c C-B d)+b (B c+(A-C) d) x}{\sqrt{a+b x} \sqrt{c+d x} \left (1+x^2\right )}\right ) \, dx,x,\tan (e+f x)\right )}{b f}\\ &=\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f}+\frac{\operatorname{Subst}\left (\int \frac{b (A c-c C-B d)+b (B c+(A-C) d) x}{\sqrt{a+b x} \sqrt{c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{b f}+\frac{(b c C+2 b B d-a C d) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 b f}\\ &=\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f}+\frac{\operatorname{Subst}\left (\int \left (\frac{i b (A c-c C-B d)-b (B c+(A-C) d)}{2 (i-x) \sqrt{a+b x} \sqrt{c+d x}}+\frac{i b (A c-c C-B d)+b (B c+(A-C) d)}{2 (i+x) \sqrt{a+b x} \sqrt{c+d x}}\right ) \, dx,x,\tan (e+f x)\right )}{b f}+\frac{(b c C+2 b B d-a C d) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b \tan (e+f x)}\right )}{b^2 f}\\ &=\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f}+\frac{((A-i B-C) (i c+d)) \operatorname{Subst}\left (\int \frac{1}{(i+x) \sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 f}+\frac{(b c C+2 b B d-a C d) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{b^2 f}+\frac{(i b (A c-c C-B d)-b (B c+(A-C) d)) \operatorname{Subst}\left (\int \frac{1}{(i-x) \sqrt{a+b x} \sqrt{c+d x}} \, dx,x,\tan (e+f x)\right )}{2 b f}\\ &=\frac{(b c C+2 b B d-a C d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b \tan (e+f x)}}{\sqrt{b} \sqrt{c+d \tan (e+f x)}}\right )}{b^{3/2} \sqrt{d} f}+\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f}+\frac{((A-i B-C) (i c+d)) \operatorname{Subst}\left (\int \frac{1}{-a+i b-(-c+i d) x^2} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{f}+\frac{(i b (A c-c C-B d)-b (B c+(A-C) d)) \operatorname{Subst}\left (\int \frac{1}{a+i b-(c+i d) x^2} \, dx,x,\frac{\sqrt{a+b \tan (e+f x)}}{\sqrt{c+d \tan (e+f x)}}\right )}{b f}\\ &=-\frac{(i A+B-i C) \sqrt{c-i d} \tanh ^{-1}\left (\frac{\sqrt{c-i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a-i b} \sqrt{c+d \tan (e+f x)}}\right )}{\sqrt{a-i b} f}-\frac{(B-i (A-C)) \sqrt{c+i d} \tanh ^{-1}\left (\frac{\sqrt{c+i d} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+i b} \sqrt{c+d \tan (e+f x)}}\right )}{\sqrt{a+i b} f}+\frac{(b c C+2 b B d-a C d) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b \tan (e+f x)}}{\sqrt{b} \sqrt{c+d \tan (e+f x)}}\right )}{b^{3/2} \sqrt{d} f}+\frac{C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b f}\\ \end{align*}
Mathematica [A] time = 4.05468, size = 441, normalized size = 1.54 \[ \frac{\frac{b \left (\sqrt{-b^2} (A c-B d-c C)+b d (A-C)+b B c\right ) \tan ^{-1}\left (\frac{\sqrt{\frac{b d}{\sqrt{-b^2}}+c} \sqrt{a+b \tan (e+f x)}}{\sqrt{\sqrt{-b^2}-a} \sqrt{c+d \tan (e+f x)}}\right )}{\sqrt{\sqrt{-b^2}-a} \sqrt{\frac{b d}{\sqrt{-b^2}}+c}}+\frac{b \left (\sqrt{-b^2} (A c-B d-c C)-b (d (A-C)+B c)\right ) \tan ^{-1}\left (\frac{\sqrt{-\frac{\sqrt{-b^2} d+b c}{b}} \sqrt{a+b \tan (e+f x)}}{\sqrt{a+\sqrt{-b^2}} \sqrt{c+d \tan (e+f x)}}\right )}{\sqrt{a+\sqrt{-b^2}} \sqrt{-\frac{\sqrt{-b^2} d+b c}{b}}}+\frac{\sqrt{b} \sqrt{c-\frac{a d}{b}} (-a C d+2 b B d+b c C) \sqrt{\frac{b (c+d \tan (e+f x))}{b c-a d}} \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b \tan (e+f x)}}{\sqrt{b} \sqrt{c-\frac{a d}{b}}}\right )}{\sqrt{d} \sqrt{c+d \tan (e+f x)}}+b C \sqrt{a+b \tan (e+f x)} \sqrt{c+d \tan (e+f x)}}{b^2 f} \]
Antiderivative was successfully verified.
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Maple [F] time = 180., size = 0, normalized size = 0. \begin{align*} \int{(A+B\tan \left ( fx+e \right ) +C \left ( \tan \left ( fx+e \right ) \right ) ^{2})\sqrt{c+d\tan \left ( fx+e \right ) }{\frac{1}{\sqrt{a+b\tan \left ( fx+e \right ) }}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (C \tan \left (f x + e\right )^{2} + B \tan \left (f x + e\right ) + A\right )} \sqrt{d \tan \left (f x + e\right ) + c}}{\sqrt{b \tan \left (f x + e\right ) + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{c + d \tan{\left (e + f x \right )}} \left (A + B \tan{\left (e + f x \right )} + C \tan ^{2}{\left (e + f x \right )}\right )}{\sqrt{a + b \tan{\left (e + f x \right )}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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